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UnRisk Insight: Goats, Wolves and Lions

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Original source (unriskinsight.blogspot.com)
Tags: math quant finance goats-wolves-lions puzzles unrisk-insight unriskinsight.blogspot.com
Clipped on: 2014-06-05

Goats, Wolves and Lions

This is a puzzle from the Austrian 2014 mathematics kangaroo contest, taken from the students' level (16years and older), which was brought to me by a friend, who is high school teacher. I think, this is really a challenging and nice one. Remember that this puzzle is one of 30 puzzles (albeit the most difficult one), and the contestants have 75 minutes of time for all of them.

I will probably publish my solution on Wednesday. I am waiting for your answers (see below what I mean with an "answer") until Wednesday noon to Andreas Binder.

The puzzle

There are three species of animals in a magic forest: lions, wolves and goats. Wolves can devour goats, and lions can devour wolves and goats. ("The stronger animal eats the weaker one".)  As this is a magic forest, a wolve, after having devoured a goat, is transmuted into a lion; a lion, after having devoured a goat, is transmuted into a wolve; and a lion having devoured a wolve becomes a goat.

At the very beginning, ther are 17 goats, 55 wolves and 6 lions in the forest. After every meal, there is one animal fewer than before; therefore after some time, there is no devouring possible any more.

What is the maximum number of animals who can live in the forest then?

A super-correct answer in my understanding

A correct answer contains

(a) the number of animals left,

(b) a devouring strategy leading to this number

(c) the proof that this is the maximal possible number of animals left.

Two versions of the puzzle: The even more difficult one.

The even more difficult one does not give you possible answers for (a). This is thought for the geniuses among you.

The kangaroo version is a multiple choice test, giving you 5 possible answers. I will write down these possible answers below the pictures. Therefore, geniuses, stop reading now.

Image (Asset 1/3) alt=